Tasks:Calculation of IR radiation lunar surface
From TeamFrednetWiki
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2009 10 22 |
| Task title: | Tasks:Calculation of IR radiation lunar surface |
| Contact person: | Marcel Belmans Ryan Weed |
| Blueprint: | (None) |
| Persons working on this task: | (No one) |
| Start: | (ASAP) |
| End: | (ASAP) |
| Group: | Category:Tasks_(Open)-lunar rover |
| Product: | (Undefined) |
| Dependencies: | (Undefined) |
| Impact: | (Undefined) |
| Percent complete: | (0%) |
| Man-hours Remaining: | (999 hours) |
| Relate page: |
Category Page_of_Tasks:Calculation of IR radiation lunar surface not found
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Description:
The sunlight that falls in on the lunar regolith is partially reflected, the other part heats the regolith up. At lunar noon the surface temperature is +/- 400K (127°C). As a result of this temperature, the regolith sends out infrared(IR)-radiation. The total amount of IR sent out can be evaluated by the grey-body-radiation formula :
Q = ε σ T^4 [W/m²]
in which sigma is a constant of 5.67E-8 W/m²K^4, T is the temperature in Kelvin and epsilon is a material property value between 0 and 1.
Now comes the next problem :
How do I calculate the amount of IR-radiation that falls in upon a structure plate of the lander when it stands on the lunar surface? The upper structural plate directed towards zenith doesn't receive regolith IR as there is no view upon the terrain around the lander, but all side and bottom plates do get a lot of IR.
,
For the thermal design of the lunar lander and rovers it is very important to quantify this effect, as it is the main heat source on the lunar surface.
I am not to good in this kind of mathematics/physics to calculate an estimated value of this effect. Can anyone help me out? --Marcel Belmans 16:09, 10 January 2009
Progress on this task is recorded in the study: Lunar regolith infrared emissions incident on an area at the surface --Anders Feder 13:58, 4 February 2009 (EST)
